Question

If $R$ and $h$ represent the horizontal range and maximum height respectively of an oblique projection whose start point (i.e. point of projection) & endpoint are in same horizontal level. Then $\frac{R^2}{8h}+2h$ represents

• A. Maximum horizontal range
• B. minimum verticle range
• C. time of fight
• D. velocity of projectile at highest point

Answer 1

The correct option is A Maximum horizontal range

$\frac{R^2}{8h}=\frac{v^2\left(2sin\theta cos\theta \right)}{g}\times \frac{v^2\left(2sin\theta cos\theta \right)}{g}\times \frac{2g}{8v^{2}si{n}^2\theta }=\frac{v^{2}co{s}^2\theta }{g}$
Now, $\frac{R^2}{8h}+2h=\frac{v^{2}co{s}^2\theta }{g}+\frac{v^{2}si{n}^2\theta }{g}=\frac{v^2}{g}=$maximum horizontal range.
hence,option $A$ is correct.