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Question

If r be the ratio of the roots of the equation ax2+bx+c=0, then (r+1)2r=

A
a2bc
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B
b2ca
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C
c2ab
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D
None of these
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Solution

The correct option is B b2ca
Given equation is ax2+bx+c=0 ...(1)
Let the root of the equation (1) be α and rα, then
α+rα=ba ...(2)
and rα2=ca ...(3)
From (2) α=ba(r+1)
Putting the value of α in (3), we get
rb2a2(r+1)2=cab2ac=(r+1)2r

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