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Question

If R=505010(1x50)100dx10(1x50)101dx, then the value of R is

A
5051
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B
5052
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C
5053
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D
5054
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Solution

The correct option is A 5051
Dr=10(1x50)101.1dxDr=[x(1x50)101]1010x(101)[1x50]100(50x49)dx=(5050)10(1x50)100[x501+1]dx=Nr(5050)DrR=NrDr=NrNr(5050)Dr=11(5050)DrNrR=5050+1=5051

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