Question

If $R_H$ is the Rydberg constant for hydrogen atoms, the ratio of $\overline{v}$ of series limits of Balmer series of hydrogen and $L{i}^{2+}$ is:

• A. $\frac{R_H}{9}$
• B. $\frac{9R_H}{4}$
• C. 9
• D. $\frac{1}{9}$

Answer 1

The correct option is D $\frac{1}{9}$

We know,

$\overline{V}\propto z^2$

where $z=$ atomic number.

$\therefore \frac{{\overline{V}}_H}{{\overline{V}}_{L{i}^{2+}}}=\frac{1^2}{3^2}=\frac{1}{9}$