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Question

If R is a relation defined as aRb, if a-b>0, then the relation is


A

Reflexive

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B

Symmetric

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C

Transitive

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D

Symmetric and transitive

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Solution

The correct option is D

Symmetric and transitive


Checking for the relation:

Step 1: Check for reflexive,

A relation is reflexive if a,aR for every aR

Assume any arbitrary element a, then |aa|=0, which shows aR.

Therefore, the relation aRb is not reflexive.

Step 2: Check for symmetric:

A relation is said to be symmetric if a,bR then b,aR

Assume that a and b be two different elements, then (a,b)R which means |ab|>0.

Since a-b=b-a, then we have

b-a>0

Thus, (b,a)R , then the relation aRb is symmetric.

Step 3: Check for transitive:

A relation is said to be symmetric if a,bR and b,cR then a,cR

Assume that a,bR and b,cR which means |ab|>0 and |bc|>0

Add both the inequalities and we get

a-c>0

Thus, a,cR , then the relation is transitive.

Hence, the correct option is (D).


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