If R is a relation from {11,12,13} to {8,10,12} defined by y=x−3. Then
A
(11,8)∈R−1
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B
(10,13)∈R
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C
(10,13)∈R−1
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D
(11,8)∈R
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Solution
The correct option is D(11,8)∈R R is a relation from {11,12,13} to {8,10,12} defined by y=x−3⇒x−y=3
Therefore, R={(11,8),(13,10)}
Hence, R−1={(8,11),(10,13)}