If R is a relation on the set A - -1- 2- 3- 4- 5- 6- 7- 8- 9- given by x R y hArr- y - 3x- then R -a- -3- 1- -6- 2- -8- 2- -9- 3-b- -3- 1- -6- 2- -9- 3-c- -3- 1- -2- 6- -3- 9-d- none of these

(d) none of theseA = 1, 2, 3, 4, 5, 6, 7, 8, 9x R y hArr; y = 3xFor x = 1, y = 3For x = 2, y = 6For x = 3, y = 9Thus, R = (1,3),(2,6),(3,9) ...

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Standard XII

Physics

Logic Gates

If R is a rel...

Question

If R is a relation on the set A = [1, 2, 3, 4, 5, 6, 7, 8, 9] given by x R y ⇔ y = 3x, then R =

(a) [(3, 1), (6, 2), (8, 2), (9, 3)]
(b) [(3, 1), (6, 2), (9, 3)]
(c) [(3, 1), (2, 6), (3, 9)]
(d) none of these

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Solution

(d) none of these

A = {1, 2, 3, 4, 5, 6, 7, 8, 9}
x R y ⇔ y = 3x
For x = 1, y = 3
For x = 2, y = 6
For x = 3, y = 9

Thus, R = {(1,3),(2,6),(3,9)}

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Similar questions

Q. If U = {1, 2, 3, 4, 5, 6, 7, 8, 9} and A = {1, 2, 3, 4}, B = {2, 4, 6, 8}, C = {3, 4, 5, 6} then prove the following :
A' = {5, 6, 7, 8, 9}

If
A = {1, 2, 3, 4}

B = {3, 4, 5, 6, 7}

C = {6, 7, 8, 9}

D = {7, 8, 9, 10}

$\begin{matrix} C o l u m n A & C o l u m n B 1. A \cup B & a . {3, 4, 6, 7} 2. A \cap B & b . \emptyset 3. (B \cap C) \cup D & c . {3, 4} 4. B \cup C \cup D & d . {3, 4, 5, 6, 7, 8, 9, 10} 5. (A \cap B) \cap (B \cup C) & e . {1, 2, 3, 4, 5, 6, 7} f . {6, 7, 8, 9, 10} g . {7} \end{matrix}$

Q. Let set U = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, set A = {2, 4, 6, 8}, and set B = {1, 3, 5, 7, 9}. Prove that (A

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Q. If

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If R is a relation on the set A = [1, 2, 3, 4, 5, 6, 7, 8, 9] given by x R y ⇔ y = 3x, then R = (a) [(3, 1), (6, 2), (8, 2), (9, 3)] (b) [(3, 1), (6, 2), (9, 3)] (c) [(3, 1), (2, 6), (3, 9)] (d) none of these

(d) none of theseA = {1, 2, 3, 4, 5, 6, 7, 8, 9}x R y ⇔ y = 3xFor x = 1, y = 3For x = 2, y = 6For x = 3, y = 9Thus, R = {(1,3),(2,6),(3,9)}

If R is a relation on the set A = [1, 2, 3, 4, 5, 6, 7, 8, 9] given by x R y ⇔ y = 3x, then R =

(a) [(3, 1), (6, 2), (8, 2), (9, 3)]
(b) [(3, 1), (6, 2), (9, 3)]
(c) [(3, 1), (2, 6), (3, 9)]
(d) none of these

(d) none of these

A = {1, 2, 3, 4, 5, 6, 7, 8, 9}
x R y ⇔ y = 3x
For x = 1, y = 3
For x = 2, y = 6
For x = 3, y = 9

Thus, R = {(1,3),(2,6),(3,9)}