If ' $R$ ' is Rydberg constant, ' $h$ ' is Planck's constant, ' $c$ ' is velocity of light, then ' $R h c$ ' has the same dimensional formula as that of

Energy

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Force

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Angular momentum

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Power

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Solution

The correct option is A Energy
$R = M^{0} L^{- 1} T^{0}$
$h = \frac{E n e r g y}{c / λ} = \frac{M^{1} L^{2} T^{- 2}}{L T^{- 1} L^{- 1}} = M^{1} L^{2} T^{- 1}$
$c = L T^{- 1}$
Therefore, $R h c = M L^{2} T^{- 2}$
Energy $= M^{1} L^{2} T^{- 2}$ ,
Force $= M^{1} L^{1} T^{- 2}$
Angular momentum $= M^{1} L^{2} T^{- 1}$
Power $= M^{1} L^{2} T^{- 3}$
Hence, option A is correct.

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