Question

If R is the radius of the octahedral voids and 'r' is the radius of the atom in close packing, then $\frac{r}{R}$ is equal to

• A. 2.42
• B. 4.76
• C. 3.22
• D. 9.12

Answer 1

The correct option is A

2.42

$\text{For}octahedralvoid,\frac{R}{r}(i.e.,\frac{r_{+}}{r_{-}}(or\left)\frac{r_{void}}{r_{-}}\right)=0.414\therefore \frac{r}{R}=\frac{1}{0.414}\approx 2.42$