If R $=$ radius of the earth and g $=$ acceleration due to gravity on the surface of the earth, the acceleration due to gravity at a distance (r>R) from the centre of the earth is proportional to

r

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r^{2}

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r^{- 2}

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r^{- 1}

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Solution

The correct option is C $r^{- 2}$
For $r > R$ , earth can be considered as a point mass.
Therefore, $F = \frac{G M m}{r^{2}}$
From the equation, $F$ is inversely proportional to $r^{2}$ .

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If R=radius of the earth and g=acceleration due to gravity on the surface of the earth, the acceleration due to gravity at a distance (r>R) from the centre of the earth is proportional to

The correct option is C r−2For r>R, earth can be considered as a point mass.Therefore, F=GMmr2From the equation, F is inversely proportional to r2.

If R $=$ radius of the earth and g $=$ acceleration due to gravity on the surface of the earth, the acceleration due to gravity at a distance (r>R) from the centre of the earth is proportional to

The correct option is C $r^{- 2}$
For $r > R$ , earth can be considered as a point mass.
Therefore, $F = \frac{G M m}{r^{2}}$
From the equation, $F$ is inversely proportional to $r^{2}$ .