If $R_{s} = 3$ , $R_{f} = 6$ then the relation between $V_{0}$ and $V_g in case of a Non-Inverting amplifying circuit.

V_{0} = 9 V_{g}

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V_{0} = 6 V_{g}

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V_{0} = 3 V_{g}

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V_{0} = V_{g}

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Solution

The correct option is C $V_{0} = 3 V_{g}$
$V_{0} = \frac{(R_{s} + R_{f})}{R_{s}} V_{0}$ . Substituting the values, we get, $V_{0} = 3 V_{g}$

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