If r, s, and t are consecutive positive multiples of 3, is rst divisible by 27,54, or both?
A
27 only
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B
54 only
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C
27and54 both
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D
None of the above.
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Solution
The correct option is C27and54 both Because r, s, and t are all multiples of 3, the product rst must have THREE 3′s as factors. Additionally, at least one of the integers must be even, so the product will have a 2 as a factor, because every other multiple of 3 is even (for example, 3,6,9,12, etc.). 27=3×3×3 can be constructed from the known prime factors and is therefore a factor of the product rst. 54=2×3×3×3 can also be constructed from the known prime factors and therefore is also factor of the product rst.