Question

If r,s are the roots of the equation x²-px+q=0, then what is the equation of the curve whose roots are ([1/r] + s) and ([1/s]+r)?

• A. px²-q(1-p)x+(1+q²)=0
• B. qx²+(p-q)x+(q²-1)=0
• C. (p-q)x²+pqx-(p+1)(q+1)=0
• D. qx²-p(q+1)x+(1+q)²=0
• E. qx²-p(q+1)x+(1+q)=0

Answer 1

The correct option is D qx²-p(q+1)x+(1+q)²=0

option d

put r=1 and s=1, then p=2 and q=1.

Roots of the curve’s equation = 2,2

Substitute values of p,q,r,s in options to check where 2,2 satisfy as roots. This happens only in option (d)