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Question

If r=x^i+y^j+z^k find (r×^i)(r×^j)+xy

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Solution

Given:r=x^i+y^j+z^k
(r×^i).(r×^j)+xy
=[(x^i+y^j+z^k)×^i].[(x^i+y^j+z^k)×^j]+xy
=[(x^i×^i+y^j×^i+z^k×^i)].[(x^i×^j+y^j×^j+z^k×^j)]+xy
=(0y+z^j).(x^k+0+0)+xy
=xy+xy=0

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