If R - x - x 2-7- S - x - x -4-4 and T - x - x 2-2-8- then which of the following is correct-A- R and T are equal sets-B- R and S are equal sets-C- S and T are equal sets-D- None of them are equal sets-

The correct option is D None of them are equal sets.R={x:x^2=7} ⇒ R = { √(7), √(7)} S={x:x+4=4} ⇒ S={0} T={x:x^2+2=8} ⇒ T = { √(6), √(6)} Hence, none of them ...

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Byju's Answer

Standard XII

Mathematics

Definition of Sets

If R = x : x ...

Question

If $R = {x : x^{2} = 7}, S = {x : x + 4 = 4}$ and $T = {x : x^{2} + 2 = 8}$ , then which of the following is correct?

R

and

T

are equal sets.

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R

and

S

are equal sets.

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S

and

T

are equal sets.

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None of them are equal sets.

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Solution

The correct option is D None of them are equal sets.
$R = {x : x^{2} = 7} \Rightarrow R = {- \sqrt{7}, \sqrt{7}} S = {x : x + 4 = 4} \Rightarrow S = {0}$
$T = {x : x^{2} + 2 = 8} \Rightarrow T = {- \sqrt{6}, \sqrt{6}}$

Hence, none of them are equal sets.

Suggest Corrections

Similar questions

Q. If

R = {x : x^{2} = 7}, S = {x : x + 4 = 4}

and

T = {x : x^{2} + 2 = 8}

, then which of the following is correct?

p, q, r, s

and

t

are in A.P. and are equal. If

q + r + s = 15

and

\frac{1}{q} + \frac{1}{r} + \frac{1}{s} = \frac{3}{5},

which is G.M. of

p

and

t

Q. If

p, q, r, s, t

and

u

are in AP, then difference

(t - r)

is equal to

If $A = {1, 4, 5, 7, 8}$ and $B = {8, 1, 5, 4, 7}$ then which of the following statements are true?

Q. If

p, q, r, s, t

and

u

are in A.P. then difference

(t - r)

is equal

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Definition of Sets

Standard XII Mathematics

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If R={x:x2=7},S={x:x+4=4} and T={x:x2+2=8}, then which of the following is correct?

The correct option is D None of them are equal sets.R={x:x2=7}⇒R={−√7,√7}S={x:x+4=4}⇒S={0} T={x:x2+2=8}⇒T={−√6,√6} Hence, none of them are equal sets.

If $R = {x : x^{2} = 7}, S = {x : x + 4 = 4}$ and $T = {x : x^{2} + 2 = 8}$ , then which of the following is correct?

The correct option is D None of them are equal sets.
$R = {x : x^{2} = 7} \Rightarrow R = {- \sqrt{7}, \sqrt{7}} S = {x : x + 4 = 4} \Rightarrow S = {0}$
$T = {x : x^{2} + 2 = 8} \Rightarrow T = {- \sqrt{6}, \sqrt{6}}$

Hence, none of them are equal sets.