If R={(x,y)/3x+2y=15 and x,y ϵ N}, the range of the relation R is________
A
{1,2}
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B
{1,2,..,5}
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C
{1,2,.,7}
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D
{3,6}
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Solution
The correct option is D{3,6} Given, 3x+2y=15 =>y=15−3x2 As both x,y are natural numbers, we should find x such that 15−3x is divisible by 2 We can see that when x=1 or 3, we get y=6 or 3 Hence, the range is 3,6