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Question

If R={(x,y):3x+2y=15 and x,yN}, the range of the relation R is .........

A
{1,2}
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B
{1,2,...,5}
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C
{1,2,...,7}
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D
{3,6}
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Solution

The correct option is C {3,6}
Since x and y belong to natural numbers we need to find positive integral solutions for 3x+2y=15

2y=153x

y=153x2

For x=0,2,4 y will become fractional which is not possible

For x5 y becomes 0 or negative which again is not possible.

Hence for x=1,3 y= 6,3$ respectively.

Hence the range is {3,6}

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