Question

If R = {(x, y) : x, y $ϵ$ Z, $x^2+y^2\le 4$ } is a relation is Z, then domain of R is

• A. {0, 1, 2}
• B. {-2, -1, 0}
• C. {-2, -1, 0, 1, 2}
• D. None of these

Answer 1

The correct option is C {-2, -1, 0, 1, 2}

We have R = {(x, y): x, y $ϵ$ z, $x^2+y^2\le 4$}
$\therefore$ = {(0,0), (0,-1), (0,1), (0, -2), (0,2) (-1,0), (1,0), (1,1), (1, -1), (-1,1), (-1,-1), (2,0), (-2,0)}
$\therefore$ Domain of R = {x : (x, y) $ϵ$ R} = {0, -1, 1, -2, 2}