Question

If radius of the earth is $6400$ km then what would be the linear velocity of any object at the equator?

Answer 1

$R=6400km$ ; The time period of Earth's rotation $T=24hr$

$\because$ $v=r\omega$

$\therefore$ $v=R\omega =R\times \frac{2\pi }{T}=\frac{6400km\times 6.28}{24hr}$

or $v=\frac{6400\times 6.28}{24}km{h}^{-1}$

$=1674.66km{h}^{-1}$

$=\frac{1674.66}{1.609}mile{h}^{-1}$

[ because $1mile=1.609km$]

or $v=1040mile{h}^{-1}$