Question

If radius of the sphere is (5.3 $\pm$ 0.1)cm. Then percentage error in its volume will be

• A. 3+6.01 $\times \frac{100}{5.3}$
• B. $\frac{1}{3}\times$ 0.01 $\times \frac{100}{5.3}$
• C. $\left(\frac{3\times 0.1}{5.3}\right)\times 100$
• D. $\frac{0.1}{5.3}\times 100$

Answer 1

The correct option is C $\left(\frac{3\times 0.1}{5.3}\right)\times 100$

Volume of sphere (v) = $\frac{4}{3}\pi {\gamma }^3$
Percentage error in volume =3 $\times \frac{\Delta \gamma }{\gamma }\times$ 100 = (3 $\times \frac{0.1}{5.3})\times$ 100