Question

If radius of the sphere is (5.3 $\pm$ 0.1)cm. Then percentage error in its volume will be

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

Volume of sphere (v) = $\frac{4}{3}\pi {\gamma }^3$
Percentage error in volume =3 $\times \frac{\Delta \gamma }{\gamma }\times$ 100 = (3 $\times \frac{0.1}{5.3})\times$ 100