If Rajesh moves along a circular path from point A(0,0) as shown in the figure and reaches diametrically opposite point B(10,0), what is his displacement vector? Given: radius of circle is 5m.
A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10^i+10^j
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10^i
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
10^j
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C10^i The displacement vector is the difference between the position vector of the final point (B here) and the initial point (A here). So, −→rB=(10^i+0^j) and −→rA=(0^i+0^j) Hence, displacement vector →Vdis=−→rB−−→rA=(10^i+0^j)−(0^i+0^j)=10^i