If Rajesh moves along a circular path from point A(0,0) as shown in the figure and reaches diametrically opposite point B(10,0), what is his displacement vector? Given: radius of circle is 5m.
A
0
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B
10^i+10^j
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C
10^i
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D
10^j
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Solution
The correct option is C10^i The displacement vector is the difference between the position vector of the final point (B here) and the initial point (A here).
So, −→rB=(10^i+0^j) and −→rA=(0^i+0^j)
Hence, displacement vector →Vdis=−→rB−−→rA=(10^i+0^j)−(0^i+0^j)=10^i