Question

If rate of formation of $O_2$ is $16$ g/hr, then rate of decomposition of $N_2{O}_5$ and rate of formation of $N{O}_2$ respectively is :

• A. cannot be calculated without knowing rate constants
• B. $108$ g/hr, $92$ g/hr
• C. $32$ g/hr, $64$ g/hr
• D. $54$ g/hr, $46$ g/hr

Answer 1

The correct option is B $108$ g/hr, $92$ g/hr

$\frac{d\left[O_2\right]}{dt}=16g/hr=\frac{16}{32}molh{r}^{-1}$

$\frac{d\left[N{O}_2\right]}{dt}=\frac{4d\left[O_2\right]}{dt}=4\times \frac{16}{32}=2molh{r}^{-1}$

$=2\times 46=92gh{r}^{-1}$

$\frac{-d\left[N_2{O}_5\right]}{dt}=\frac{2d\left[O_2\right]}{dt}=2\times \frac{16}{32}$

$=1molh{r}^{-1}=1\times 108=108gh{r}^{-1}$