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Question

If ratio of the sum of n terms of 2 different A.P. is 3n+24n+23, then the ratio of 10th term is

A
5999
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B
5099
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C
6999
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D
5979
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Solution

The correct option is A 5999
Given : SnSn=3n+24n+23
Putting n2n1, we get
TnTn=3(2n1)+24(2n1)+23TnTn=6n18n+19T10T10=5999

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