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Question

If Re(1+iy)3=−26, where y is a real number, then the value of |y| is

A
2
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B
3
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C
4
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D
6
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E
9
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Solution

The correct option is C 3
Let z=(1+iy)3
=1+3iy+3i2y2+i3y3
=1+3iy3y2iy3
=(13y2)+(3yy3)i
Now, Re(z)=26
13y2=26
27=3y2y2=9
y=±3 or |y|=3

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