Question

If reading of voltmeter $V$ shown in the figure at resonance is $200V$, then the quality factor of the circuit is:

• A. $2$
• B. $4$
• C. $1$
• D. $3$

Answer 1

The correct option is B $4$

The voltage across capacitor in resonant condition gives a relation between voltage across the capacitor and source voltage as-

$V_C=Q\times V_S$

$\therefore 200v=q\times \left(50v\right)$

$Q=4$