Question

If resistance of $100\Omega$ and the inductance of $0.5$ henry and capacitance of $10\times {10}^6$ farad are connected in series through $50$Hz A.C supp;y, then impedence is

• A. $1.8765\Omega$
• B. $18.76\Omega$
• C. $187.6\Omega$
• D. $101.3\Omega$

Answer 1

Answer: (C)

$187.6\Omega$

$z=\sqrt{R^2+{(\omega L-\frac{1}{\omega C})}^2}$
Here $R=100W,L=0.5henry,C=10\times {10}^{6}farad$\omega=2p \pi=100\pi$