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Question

If resistance of wire at 50C is 5 R Ω and 100C is 6R Ω, find resistance of 0C.

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Solution

We know that,
Rt=R0(1+αt)
Where R1 is the resistance of the wire at t0C
R0 is the resistance of the wire at 00C
and α is the temperature coifficient of resistance.
R50=R0(1+50α)(i)
R100=R0(1+100α)(ii)
From (i), R50R0=50αR0(iii)
From (ii), R100R0=100αR0(iv)
Dividing (iii) by (iv), we get
R50R0R100R0=12
Here R50=5Ω and R100=6Ω
5R06R0=12
or 6R0=102R0 or, R0=4Ω

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