The correct option is
A linear momentum of the system does not change with time
From Newtons's
2nd law (valid in an inertial frame of reference),
→Fext=−→dPdt If net external force on system is zero,
→Fext=0 Hence, linear momentum of system will remain constant.
If a couple force (equal in magnitude and opposite in direction) acts on the system
Net external force on system
→Fext=+F−F=0 However, w.r.t point
A, a net moment of one of the forces
F exists in clockwise direction.
i.e
→τext≠0 ...(i) & →τext=−→dLdt ...(ii) From Eq
(i) & (ii):
−→dLdt≠0 ∴→L≠constant Hence angular momentum of system can change with time, even though
→Fext=0.
For
K.E of system to be constant, all collisions between the particles of the system should be elastic and work done by any internal non conservative forces should also be zero.
Hence, option A is correct.