If $A = x y, B = y z$ and $C = z x,$ then find $A B C = . . . . . . . . .$

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Solution

We have,
$A = x y, B = y z, C = z x$

So,
$A B C = x y \times y z \times z x$

$A B C = (x y z)^{2}$

Hence, this is the answer.

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