If tan- a - b- then the value of E -asin- bcos -asin- b cos- is -A- a2-b2-a2-b2B- a2-b-a-bC- a-b-a2-b2D- a2-b2-a2-b2

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Higher Order Derivatives

If tanθ= a / ...

Question

If $t a n θ = \frac{a}{b}, t h e n t h e v a l u e o f E = \frac{a s i n θ - b c o s θ}{a s i n θ + b c o s θ} i s -$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

If $t a n θ = \frac{a}{b}, t h e n t h e v a l u e o f E = \frac{a s i n θ - b c o s θ}{a s i n θ + b c o s θ} i s -$

t a n θ = \frac{a}{b}

\frac{a sin θ - b cos θ}{a sin θ + b cos θ} = \frac{a^{2} - b^{2}}{a^{2} + b^{2}}

If $t a n θ = \frac{a}{b}$ , show that $\frac{a s i n θ - b c o s θ}{a s i n θ + b c o s θ} = \frac{a^{2} - b^{2}}{a^{2} + b^{2}}$

\pm \sqrt{a^{2} + b^{2} + c^{2}}

\pm \sqrt{a^{2} + b^{2} - c^{2}}

\pm \sqrt{c^{2} - a^{2} - b^{2}}

\sqrt{a 2 + b 2}

Join BYJU'S Learning Program