Question

If Rocket A is made of 70 identical parts and Rocket B is made of 35 identical parts, then the length of the parts of each rocket can be compared as

• A. A > B
• B. B > A
• C. A = B

Answer 1

The correct option is C A = B

For Rocket A:
Total length of Rocket A $=3430cm$.
Total number of parts in Rocket A $=70$

So, the length of each part of Rocket A will be
$=3430cm÷70$

The number $3430$ in its exapnded form can be written as:
$3430=3000+400+30$

Here, Divisor = $3430$
and Dividend = $70$.

So, calculating $=3430÷70$ using the box method,

Adding all the partial quotients, you get the final quotient as: $40+5+4=49$.

So, $3430cm÷70=49cm$.

Therefore, each part of Rocket A will be $49cm$ long.

For Rocket B:
Total length is $1715cm$.
Total number of parts in it is $35$.

So, the length of each part of Rocket B will be $=1715cm÷35$.

So, here, Dividend = $1715$
and Divisor = $35$.

The number $1715$ in its expanded form can be written as: $1715=1000+700+10+5$.

So, calculating $1715÷35$ using the box method, you get the following:

Adding the partial quotients, you get the final quotient as: $20+20+5+4=49$.

So, the length of each part of Rocket B is also $49cm$.

Hence, comparing the lengths of the parts of both the rockets, you get, $A=B$.