If Rohit moves along a circular path from point A(0,0) as shown in the figure and reaches diametrically opposite point B(5,0), what is his displacement vector? Given: radius of circle is 2.5 unit.
A
0
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B
5^i+5^j
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C
5^j
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D
5^i
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Solution
The correct option is D5^i The displacement vector is the difference between the position vector of the final point (B here) and the initial point (A here).
So, −→rB=(5^i+0^j) and −→rA=(0^i+0^j)
Hence, displacement is given by →S=−→rB−−→rA=(5^i+0^j)−(0^i+0^j)=5^i