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Question

If Rolle's theorem is applied to f(x)=sinx+cosx+1;x[π,3π2], then the value of c is ______.

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Solution

Given,
f(x)=sinx+cosx+1;x[π,3π2]
We have, f(π)=01+1=0.
Again f(3π2)=1+0+1=0.
Also f(x) is continuous in the given interval and is differentiable in (π,3π2).
So all the conditions of Rolle's theorem are satisfied by f(x) in the given interval.
Then a real number c (π,3π2) such that,
f(c)=0
or, coscsinc=0
or, tanc=1
or, c=nπ+π4.
Since c(π,3π2). so c=3π4.

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