CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If Rolle’s theorem holds for the function f(x)=x3ax2+bx4,x[1,2]  with f(43)=0, then ordered pair (a, b) is equal to :
 
  1. (5,8)
  2. (5,8)
  3. (5,8)
  4. (5,8)


Solution

The correct option is B (5,8)
f(1)=f(2)
1a+b4=84a+2b4
3ab=7     (1)
f(x)=3x22ax+b
f(43)=03×16983a+b=0
8a+3b=16   (2)
From (1) and (2)
a=5,b=8

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image