If roots of equation ax2+bx+c=0, are distinct and less than unity, then which of the following is/are true?
A
9a+6b+4c25a+10b+4c is positive
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
9a+3b+ca+b+c is positve
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
9a+6b+4c25a+10+4c is negative
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
c4a+2b+c is negative
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct options are A9a+6b+4c25a+10b+4c is positive B9a+3b+ca+b+c is positve f(32)f(52)>0⇒9a+6b+4c25a+10b+4c is positive & f(3)f(1)>0⇒9a+3b+ca+b+c is positive we cannot comment on f(0)f(2). Same in downward parabola