wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If roots of the equation ax2+bx+c=0 are α,β, then the equation whose roots are 1+α1α,1+β1β, where α1,β1 is

A
a(x21)+b(x1)2+c(x+1)2=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a(x+1)2+b(x21)+c(x+1)=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a(x1)2+b(x21)+c(x+1)2=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
a(x1)2+b(x21)+c(x1)=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C a(x1)2+b(x21)+c(x+1)2=0
Let 1+α1α=y
1+α=yαyα=y1y+1
Now, α is the root of the equation ax2+bx+c=0
aα2+bα+c=0
a(y1y+1)2+b(y1y+1)+c=0

Hence, the required equation is a(x1)2+b(x21)+c(x+1)2=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Transformation of Roots: Linear Combination of Roots
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon