CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If roots of the equation $$x^2-bx+c=0$$ be two consecutive integers, then $$b^2-4c$$ equals :


A
2
loader
B
3
loader
C
2
loader
D
1
loader

Solution

The correct option is D $$1$$
Given equation is $$x^2-bx+c=0$$
Let the roots be $$\alpha$$ and $$\alpha+1$$
Therefore, $$2\alpha+1=b$$
$$\Rightarrow \alpha(\alpha+1)=c$$
Hence, $$b^2-4c$$
$$=(2\alpha+1)^2-4\alpha(\alpha+1)$$
$$=1$$

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image