Question

If Rs 782 is to be divided into three parts, proportional to $\frac{1}{2},\frac{2}{3},\frac{3}{4}$then the first part is

• A. Rs 182
• B. Rs 190
• C. Rs 196
• D. Rs 204

Answer 1

The correct option is D Rs 204

Given number = 782
$\{\frac{1}{2}+\frac{2}{3}+\frac{3}{4}\}\cdot x=782$
$\left\{\frac{12+16+18}{24}\right\}\times x=782$
$\left\{\frac{46}{24}\right\}\cdot x=782$
$\left\{\frac{23}{12}\right\}\cdot x=782$
x = 408
now the first part = $\frac{1}{2}\cdot x=\frac{1}{2}\cdot 408=204$
second part = $\frac{2}{3}\cdot x=\frac{2}{3}\cdot 408=272$
third part = $\frac{3}{4}\cdot x=\frac{3}{4}\cdot 408=306$