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Question

If rth term is the middle term in the expansion of x2-12x20, then r+3th term is
(a) C1420x214

(b) C1220 x22-12

(c) -C720 x, 2-13

(d) none of these

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Solution

(c) -C720 x× 2-13
Here n is even
So, The middle term in the given expansion is 202+1th=11th term
Therefore, (r + 3)th term is the 14th term.

T14=C1320 (x2)20-13 -12x13=-113 C1320 x14-13213=-C720 x2-13

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