If S1,S2,S3,...Sn are the sums of infinite geometric series whose first terms are 1,2,3,.....,n and whose common ration are 12,13,14,...,1n+1 respectively, then find the value of S12+S22+S32+....+S2n−12.
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Solution
Sr=r+1∴S2r=(r+1)2 ∴S21+S22+..S22n−1=2n−1Σr=1s2r =22+32+42+..(2n)2 [12+22+32+..N2]−1 Where N=2n 16N(N+1)(2N+1)−1 13n(2n+1)(4n+1)−1