If s=2t3−6t2+at+5 is the distance traveled by a particle at time t and if the velocity is −3 when its acceleration is zero, then the value of a is
A
−3
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B
3
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C
4
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D
−4
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E
2
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Solution
The correct option is E3 Given, s=2t3−6t2+at+5 Velocity, V=dsdt=6t2−12t+a Acceleration, A=d2sdt2=12t−12 Since, A=0 ⇒12t−12=0 ⇒t=1 At t=1, V=6−12+a=a−6 It is given that, at A=0, V=−3 ⇒a−6=−3 ⇒a=3