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B
8x+sinx
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C
8−sinx
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D
8+sinx
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Solution
The correct option is D8+sinx Given, S=4x2−sinx d2Sdx2⇒d(dSdx)dx
So, we have dSdx=d(4x2−sinx)dx ⇒4dx2dx−dsinxdx=8x−cosx
Thus, d2Sdx2=d(8x−cosx)dx ⇒8dxdx−dcosxdx=8+sinx