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Question

If SA=2m+(2m+1)+(2m+2)+...+4m and SB=(2m+1)+(2m+3)+(2m+5)+...+(4m1), then

A
SASB=2+1m
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B
SASB=43+23m
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C
SASB=43+1m
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D
SASB=13+1m
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Solution

The correct option is A SASB=2+1m
SA=2m+(2m+1)+(2m+2)+...+4m
Number of terms in the series SA is 2m+1
SA=2m+12(4m+2m)SA=3m(2m+1)

SB=(2m+1)+(2m+3)+...+(4m1)
Number of terms in the series SB is m
SB=m2[2m+1+4m1]SB=3m2

Therefore,
SASB=2m+1m=2+1m

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