If $S_{A}$ and $S_{B}$ represents the displacement of block and plank w.r.t. ground respectively when block seperates, then

S_{A}

4 V \sqrt{\frac{l}{3 g}} - \frac{2}{3} l

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S_{A}

4 V \sqrt{\frac{l}{g}} - \frac{2}{3} l

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S_{B}

4 V \sqrt{\frac{l}{3 g}} - \frac{5}{3} l

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S_{B}

4 V \sqrt{\frac{l}{g}} - \frac{1}{3} l

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Solution

The correct options are
A $S_{A}$ = $4 V \sqrt{\frac{l}{3 g}} - \frac{2}{3} l$
C $S_{B}$ = $4 V \sqrt{\frac{l}{3 g}} - \frac{5}{3} l$

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If SA and SB represents the displacement of block and plank w.r.t. ground respectively when block seperates, then

The correct options are A SA=4V√l3g−23l C SB=4V√l3g−53l

If $S_{A}$ and $S_{B}$ represents the displacement of block and plank w.r.t. ground respectively when block seperates, then

The correct options are
A $S_{A}$ = $4 V \sqrt{\frac{l}{3 g}} - \frac{2}{3} l$
C $S_{B}$ = $4 V \sqrt{\frac{l}{3 g}} - \frac{5}{3} l$