If $s = a e^{t} + b e^{- t}$ is the equation of motion of a particle, then its acceleration is equal to

s

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2 s

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3 s

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4 s

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Solution

The correct option is A $s$
$s = a e^{t} + b e^{- t}$
Velocity $v = \frac{d s}{d t} = a e^{t} - b e^{- t}$
Acceleration $= \frac{d v}{d t} = a e^{t} + b e^{- t} = s$

Suggest Corrections

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