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Question

If S and T are respectively the sum and the sum of the squares of n successive positive integers beginning with ′a′ then show that nT−S2

A
Independent of a
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B
Dependent of a
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C
Varies from condition to condition
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D
None of these
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Solution

The correct option is A Independent of a
According to question
S=a+a+1+a+2+a+3+......+(a+n-1)

=na+n(n1)2 (1)

T=a2+(a+1)2+....+(a+n1)2

T=na2+2an(n1)2+N2'

nT=n2a2+an2(n1)+nN2

and S2=n2a2+n2(n1)24+an2(n1)

nTS2=nN2n2(n1)24

Clearly nTS2 is independent of a.

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