If S and T are two sets such that S has 21 elements- T has 32 elements and S- T has 11 elements- thenfind the number of elements in S- T-

The correct option is C 42 Given n(S) = 21 , n(T) = 32, n ( S∩ T ) = 11 Now n(S) + n(T) = #160;n( S∩ T ) + n( ...

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Standard XII

Mathematics

Union

If S and ...

Question

If $S$ and $T$ are two sets such that $S$ has $21$ elements, $T$ has $32$ elements and $S \cap T$ has $11$ elements, then
find the number of elements in $S \cup T$ .

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Solution

The correct option is C $42$
Given $n (S) = 21$ , $n (T) = 32,$ $n$ ( $S \cap T$ ) $= 11$
Now $n (S) + n (T) = n ($ $S \cap T$ ) $+ n ($ $S \cup T$ )
$\Rightarrow$ $n ($ $S \cup T$ $) = 21 + 32 - 11 = 42$ .

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If S and T are two sets such that S has 21 elements, T has 32 elements and S∩T has 11 elements, thenfind the number of elements in S∪T.

The correct option is C 42Given n(S)=21, n(T)=32, n(S∩T) =11Now n(S)+n(T)=n( S∩T) +n(S∪T)⇒ n( S∪T)=21+32−11=42.

If $S$ and $T$ are two sets such that $S$ has $21$ elements, $T$ has $32$ elements and $S \cap T$ has $11$ elements, then
find the number of elements in $S \cup T$ .

The correct option is C $42$
Given $n (S) = 21$ , $n (T) = 32,$ $n$ ( $S \cap T$ ) $= 11$
Now $n (S) + n (T) = n ($ $S \cap T$ ) $+ n ($ $S \cup T$ )
$\Rightarrow$ $n ($ $S \cup T$ $) = 21 + 32 - 11 = 42$ .