If S be the set of all triangles and f:S→R+,f(Δ) =Area of Δ, then f is.
A
one-one onto
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B
one-one into
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C
many-one onto
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D
many-one into
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Solution
The correct option is C many-one onto There can be infinitely many triangles with the same area. Hence the above function is many one. Now for every element (△) in R+ there is atleast one triangle in S which has Area=△. Hence for every element in R+ there is atleast one corresponding element in S . Hence f(x) is an onto function.